Chicago White Sox first baseman Jose Abreu won the American League MVP award Thursday after helping power the team to its first playoff berth in 12 years.
The 33-year-old slugger received 21 of 30 first-place votes and 374 points in voting announced by the Baseball Writers’ Association of America.
Cleveland Indians third baseman Jose Ramirez was second with eight first-place votes and 303 points, and New York Yankees second baseman DJ LeMahieu, who won the AL batting crown, followed with one first-place vote and 230 points.
Voting by the BBWAA was completed by the start of the playoffs. It has voted for the award since 1931.
Abreu led the majors with 60 RBIs and 148 total bases, and topped the AL with 76 hits and a .617 slugging percentage. He played in all 60 games during the virus-shortened season as Chicago claimed a wild-card spot.
Abreu batted .317 with 19 home runs, connecting six times in a three-game series against the Cubs in late August. That barrage of long balls at Wrigley Field was part of his 22-game hitting streak, the longest in the majors this year.
Ramirez hit .292 with 17 home runs and 46 RBIs. His late-season surge helped Cleveland clinch a wild-card spot. No Indians player has won the AL MVP since Al Rosen in 1953.
LeMahieu led the majors with a .364 batting average. Able to play all around the infield, he is now a free agent.
AL Cy Young Award winner Shane Bieber of Cleveland was fourth and Angels outfielder Mike Trout was fifth. A three-time AL MVP, Trout had finished in the top four every season since he was AL Rookie of the Year in 2012.